An example:

Say you wanted to add “ShowerThoughts” from lemmy.world.

  1. Go to https://lemmy.world/c/showerthoughts
  2. In the right column, Look for the blurb that says something like “You are not logged in. However you can subscribe from another Fediverse account, for example Lemmy or Mastodon. To do this, paste the following into the search field of your instance: !showerthoughts@lemmy.world”
  3. At the bottom of that blurb, you see where it says “!showerthoughts@lemmy.world”? You copy that.
  4. Then you go to the search page on this site(from the search button in the upper right of this page), and you search for what you just copied. You may need to search for it 2-3 times for it to come up.
  5. One of the results will be that community. Click the link, and then click join in the right column.

From that point forward, you should see posts from that community in your feed on this site.

  • uki@talk.macstack.netEnglish
    1·
    1 year ago

    What I want is to follow specific people that are not here. They’re in some fediverse site, but neither is a Lemmy site. Is that possible?

    These https://bitbang.social/@NanoRaptor

    https://colony.red/@spacejim

    USING MY ACCOUNT HERE, I’d like to be able to comment/reply on their posts, and get notifications for their posts/replies, here.

    I thought this whole fediverse thing allowed that.

    If I enter those addresses in the search field here, I get something that looks like their… accounts… damn I forget the name. BUT, I don’t see any link/button that says “follow”. So the search engine here in this site CAN find them, one of them replied to one of my posts here, so THEY can see my post and interact with me.

    • obvs@talk.macstack.netOPMEnglish
      1·
      1 year ago

      So if you want to view those people’s accounts, you can search using this format:

      @spacejim@colony.red

      and you can see their accounts and respond to them, and they can respond to you, but it doesn’t look like there’s an easy way to subscribe to their accounts yet.