What dimensional space are the people arranging themselves in?
But seriously, this reminds me of a time at my former (FAANG) employer where HR sent out a 40-minute video about not being an asshole and avoiding lawsuits.
12 minutes or so in, they say “as the number of people in a group increases, the number of potential 1:1 interactions increases exponentially.” I thought “actually n(n-1)/2 but whatever”, and finished the video intending to get on with my life.
My inbox was FULL of engineers who were irate. “HR have proven themselves to be fools!” “I expect the company to never ask me to waste my time on their bullshit again.” “Once again non-technical people talking out their asses.”
HR sent a global apology for the error, asked everybody to not watch the video while they fixed it, and released a patched version the next day.
HR should have replied with a “this was a test on how not to be an asshole and you’ve all failed. You must take the whole training again”
What’s weirder is that the bottom two are 6 feef apart
Americans will use anything but metric
I wouldn’t touch the metric system with a 10-foof pole.
I’m a little sad nobody has done the correct math and it’s been too long for me to do it off the top of my head lol.
A2+B2=C^2? What distance are the diagonals if the sides are 6’ apart?
6x6 + 6x6 = sqrt72 = 8.49’ !
I did it bois. Ty calculator for sqrt72…
Now do the conversion factor from feef to feet!
The diagonal is 6ft. The side is 6 ft. So 6² + 6feef² = 6²
1 feef = 0ft
Simple: they live in doom
It’s a tetrahedron, duh
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No one is mentioning that the math doesn’t work out if the staight line distances are constraints then the diagonals are not correct, and vice versa.
You do understand what the Pythagorean theorem is, right?
i think that is the joke
If the 6 feet is from head to head, couldn’t you flip two people upside down?
