• EpeeGnome@lemm.ee
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    22 hours ago

    A square? A square?! Wake up sheeple! That things not even a rombus! Don’t you see the lies? Look at the lines! Look! Not all rhombuses are squares, but all squares are rhombuses! All squares are rhombuses and look at this thing they try to call a square. Where are the parallel lines? There’s got to be parallel lines, don’t you see, or then it’s not a rombus and all squares are rhombuses. Don’t forget that, don’t let them take that fact from you and perpetuate their geometric lies. Does no one even remember what a rombus is? This is, this is basic geometry here that you should have learned in middle school or elementary school, but then you just forget it, and let people trick you with these misleading definitions and fancy diagrams but you have to remember that a Square. Is. A. Rombus.

  • werefreeatlast@lemmy.world
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    1 day ago

    This is what AI would give you after countless tries strating with a triangle and having gone up the Pentagon and down to two pairs of unconnected parallel lines…but what if all equally sized lines were connected? Bam! This

      • AdrianTheFrog@lemmy.world
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        12 hours ago

        I thought this couldn’t be true, so using one of the newer models (4bit flux) I told it to make a 5 sided star, and then put lines around the outside

        lol this is very weird, did they forbid it from looking at pentagons in the training data or something? it can’t do The Pentagon either, it gives it 8-12 sides instead

        • Hackworth@lemmy.world
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          5 hours ago

          I don’t really know, but I think it’s mostly to do with pentagons being under-represented in the world in general. That and the specific way that a pentagon breaks symmetry. But it’s not completely impossible to get em to make one. After a lot of futzing around, o1 wrote this prompt, which seems to work 50% of the time with FLUX [pro]:

          An illustration of a regular pentagon shape: a flat, two-dimensional geometric figure with five equal straight sides and five equal angles, drawn with black lines on a white background, centered in the image.

  • RememberTheApollo_@lemmy.world
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    2 days ago

    Kinda forgot the sides being parallel part. Like missing a step in assembling IKEA furniture, its not gonna turn out right.

      • angrystego@lemmy.world
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        1 day ago

        This one is enclosed and contiguous though, the lines of the triangle end where the circular line starts. (The rest is just a drafting residue.)

        • finitebanjo@lemmy.world
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          1 day ago

          No, it is 2 contiguous regions. The line of separation is the bounding line of a “shape.”

          Otherwise, the entire whitespace outside of the region is also part of the shape, as is anything it touches.

  • LarmyOfLone@lemm.ee
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    1 day ago

    Now make a square out of squiggly yarn

    String theorists claim this is the true shape of spacetime!

          • wholookshere@lemmy.blahaj.zone
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            1 day ago

            Only true in Cartesian coordinates.

            A straight line in polar coordinates with the same tangent would be a circle.

            EDIT: it is still a “straight” line. But then the result of a square on a surface is not the same shape any more.

            • ltxrtquq@lemmy.ml
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              1 day ago

              A straight line in polar coordinates with the same tangent would be a circle.

              I’m not sure that’s true. In non-euclidean geometry it might be, but aren’t polar coordinates just an alternative way of expressing cartesian?

              Looking at a libre textbook, it seems to be showing that a tangent line in polar coordinates is still a straight line, not a circle.

              • wholookshere@lemmy.blahaj.zone
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                17 hours ago

                I’m saying that the tangent of a straight line in Cartesian coordinates, projected into polar, does not have constant tangent. A line with a constant tangent in polar, would look like a circle in Cartesian.

                • ltxrtquq@lemmy.ml
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                  16 hours ago

                  Polar Functions and dydx

                  We are interested in the lines tangent a given graph, regardless of whether that graph is produced by rectangular, parametric, or polar equations. In each of these contexts, the slope of the tangent line is dydx. Given r=f(θ), we are generally not concerned with r′=f′(θ); that describes how fast r changes with respect to θ. Instead, we will use x=f(θ)cosθ, y=f(θ)sinθ to compute dydx.

                  From the link above. I really don’t understand why you seem to think a tangent line in polar coordinates would be a circle.

    • Kairos@lemmy.today
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      2 days ago

      This is also not a polygon. It has infinite and 2 sides at the same time.