[SOLVED]
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find /home/$USER -maxdepth 1 -type f -executable -exec sh -c 'head -n 1 "$1" | grep -q "^#!/bin/bash" && cp "$1" /home/bob/Documents/Linux/Regularly_Copied_files_crontab' sh {} \;
edit: I just want to copy scripts in /home/$USER
folder, not all the other subfolders.
edit 2: I think the better approach here would be to have two conditions.
- The file is in /home/$USER/ and not in it’s subfolders.
- The file’s first line should be
I don’t actually need all executable files, I just want my bash scripts, but unfortunately, I don’t have the good habit of giving the .sh extensions to all of them. These files are all executable, they all have a shebang line (`#!/bin/bash) as their first line, how can I copy them elsewhere? I mean, I know how the copy commands work, but I don’t know if I can specify the pattern here.
How would I specify a cp
command to only copy bash scripts
to my docs folder
?
Intended Use case: I am trying to create a command to copy all the bash scripts
I have created in my home folder to my Documents
folder. My docs folder is synced everyday, so I won’t ever lose my scripts as they would be stored in the cloud.
find ~ -type f -executable
find /home/user -type f -perm /u+x -not -path “/home/user/Documents” -exec cp {} ~/Documents ;
___
find /home/user -type f -perm /u+x -not -path "/home/user/Documents" -exec cp {} ~/Documents \;
Run it without exec -parameter to get a list of files affected, I’d guess that that will catch more than you want as it only checks that it’s a normal file and has the excecutable -bit on. To get only bash-scripts you’d first need to get a list of files with find and then check if it’s a script with something (grep or maybe file should work) and copy based on that result, but it shouldn’t be too difficult to write a script for it.
find ~ -type f -executable
will give you a list of all executable files You can probably use find’s -exec to move them all.
Is using another script okay?
#!/bin/bash docs_folder=/some/folder cd files=(*) for f in "${files[@]}"; do [[ "$(cat "$f" | head -n 1)" = '#!/bin/bash' ]] && cp "$f" "$docs_folder/$f" done
It’s fucking up the ampersands for some reason.
grep -rl '#!/bin/bash' . | xargs -I {} cp {} /path/to/destination/
One problem, I think it’s copying all the files inside folder
/home/$USER
whereas I just want the bash files which are in/home/$USER
exlcluding all the subfolders. The commandgrep -rl '#!/bin/bash' . | xargs -I {} cp {} /path/to/destination/
won’t exclude subfolders.deleted by creator
grep -l ‘#!/bin/bash’ . | xargs -I {} cp {} /path/to/destination/
grep -l '#!/bin/bash' . | xargs -I {} cp {} /home/$USER/Documents/Linux/Regularly_Copied_files_crontab grep: .: Is a directory
I don’t know what’s happening here
deleted by creator
Combine
grep -l
to find files with the shebang andcp
to copy them to your docs folder. You can one-liner pipe or save the grep results to file and iterate. If the directories are nested and some of these files have the same name, they’ll conflict if you don’t include most of the original path in the cp target.If you need them to be executable I think I’d use
find
first.